Silver chloride dissolves in excess of ammonium hydroxide solution. The cation present in the resulting solution is:

[A g (N H_{3})_{6}]^{+}

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[A g (N H_{3})_{4}]^{+}

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A g^{+}

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[A g (N H_{3})_{2}]^{+}

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Solution

The correct option is D $[A g (N H_{3})_{2}]^{+}$
$A g C l + 2 N H_{4} O H — \to {A g (N H_{3})_{2}}^{+} C l^{-} + H_{2} O$

Silver chloride dissolves in excess of ammonium hydroxide solution to produce $[A g (N H_{3})_{2}]^{+}$ and $C l^{-}$ .

The cation is $[A g (N H_{3})_{2}]^{+}$ . Hence, option D is correct.

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Silver chloride dissolves in excess of ammonium hydroxide solution. The cation present in the resulting solution is:

The correct option is D [Ag(NH3)2]+AgCl+2NH4OH—→Ag(NH3)2+Cl−+H2OSilver chloride dissolves in excess of ammonium hydroxide solution to produce [Ag(NH3)2]+ and Cl−.The cation is [Ag(NH3)2]+. Hence, option D is correct.