Question

Silver is removed electrolytically from 200 mL of a 0.1N solution of $AgN{O}_3$ by a current of 0.1 ampere. How long will it take to remove half of the silver from the solution?

• A. 100 sec
• B. 16 sec
• C. 100 sec
• D. 9650 sec

Answer 1

The correct option is D 9650 sec

Meq.of Ag = $200\times 0.1=20$
Meq. of Ag to be deposited = $\frac{20}{2}=10$;
Now use Meq of Ag = $\frac{i\times t}{96500}\times 1000$
or $10=\frac{0.1\times t\times 1000}{96500}$
$\therefore$ t=9650 sec