Question

Silver nitrate is 85% by mass. To prepare 125ml of 0.05molar silver nitrate solution , silver nitrate sample required is?

Answer 1

Number of moles of silver nitrate to prepare = molarity*volume
= 0.05*0.125 = (1/20)*(1/8) = (1/160)

weight of silver nitrate = (1/160)* molecular mass
=(1/160)* 169.87 gm
= 1.062 gms
The sample availabe is 85% by mass.
So, the amount of sample required is:
= 1.062*(100/85)
= 1.25 gms