- p- q - - p- q is logically equivalent to

The correct option is A ∼ p ∼( p∨ q ) ∨( ∼ p∧ q ) =( ∼ p∧∼ q ) ∨( ∼ p∧ q ) =∼ p∧( ∼ q∨ q ) =∼ p ...

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Properties of Composite Function

∼ p∨ q ∨ ∼ p∧...

Question

$\sim (p \lor q) \lor (\sim p \land q)$ is logically equivalent to

\sim p

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p

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q

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\sim q

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