- p - q is equal toA- P - qB - - p - qC - - p - qD- p - q

The correct option is A p ∧ q(∼ (∼ p))∧ q=p ∧ q ...

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Negation

∼∼ p ∧ q is e...

Question

$\sim (\sim p)) \land q$ is equal to

\sim p \land q

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p \land q

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p \land \sim q

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\sim p \land \sim q

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Solution

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Similar questions

\sim ((\sim p) \land q)

\sim (\sim p)) \land q

\sim ((\sim p) \land q)

$\sim (\sim p \land q)$ is logically equivalent to

(p \land \sim q) \lor q \lor (\sim p \land q)

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