We have,
(62581)−34×⎡⎣(425)−32÷(23)−3⎤⎦
=(81625)34×⎡⎣(254)32÷(32)3⎤⎦
=(3454)34×[(254)×(52)×(23)3]
=(35)3×[(1258)×(23)3]
=(27125)×(12527)
=1
Hence, this is the answer.