Simple pendulum of length 1 is made to oscillate with amplitude of 45 degrees- The acceleration due to gravity is g- Let T 0-2 -1- g - The time period of oscillation of this pendulum will beA- Dependent on whether it swings in a plane aligned with the north-south or east west directions-B- slightly less than T0C- T0- irrespective of the amplitudeD- Slightly more than T0

The correct option is D Slightly more than T=2π√(l/g) ( 1+θ^2_0/16 ) ...

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Standard XII

Physics

Physical Pendulum

Simple pendul...

Question

Simple pendulum of length l is made to oscillate with amplitude of 45 degrees.The acceleration due to gravity is g. Let $T_{0} = 2 π \sqrt{\frac{l}{g}}$ . The time period of oscillation of this pendulum will be

, irrespective of the amplitude

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slightly less than

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Slightly more than

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Dependent on whether it swings in a plane aligned with the north-south or east west directions.

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Solution

The correct option is C Slightly more than
$T = 2 π \sqrt{\frac{l}{g}} (1 + \frac{θ_{0}^{2}}{16})$

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Simple pendulum of length l is made to oscillate with amplitude of 45 degrees.The acceleration due to gravity is g. Let T0=2π√lg. The time period of oscillation of this pendulum will be

The correct option is C Slightly more than T=2π√lg(1+θ2016)

Simple pendulum of length l is made to oscillate with amplitude of 45 degrees.The acceleration due to gravity is g. Let $T_{0} = 2 π \sqrt{\frac{l}{g}}$ . The time period of oscillation of this pendulum will be

The correct option is C Slightly more than
$T = 2 π \sqrt{\frac{l}{g}} (1 + \frac{θ_{0}^{2}}{16})$