Simplify: 0.9÷0.3×0.3
If √0.03×0.3×p=0.3×0.03×√qthen pq=?
Simplify (i) 32x-0.45y2 (ii) 0.3x-0.2y0.9a-0.02b (iii) 0.3a-0.2b0.09a2+0.06ab+0.04b2 (iv) 0.73+0.33+3×0.7×0.30.7+0.3 (v) 3.53-1.53-3×3.5×1.53.5-1.5
The normality of 0.1MB(OH)3 is