Question

Simplify:
$\frac{16m^3{y}^2}{4m^{2}y}$

Answer 1

$$\begin{gathered} \frac{16m^3{y}^2}{4m^{2}y} \\ =\frac{16\times m\times m\times m\times y\times y}{4\times m\times m\times y} \\ =4m^{(3-2)}{y}^{(2-1)} \\ =4my \end{gathered}$$