Simplify -2-5-3-5-4-5-

The correct option is B 1/( 24)^5By the Laws of Exponents, we know that a^m× b^m=(ab)^m ⇒ ( 2)^ 5×(3)^ 5×(4)^ 5 =(( 2)×3×4)^ 5 =( 24)^ 5=1/( 24)^5 ...

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Byju's Answer

Standard VII

Mathematics

Exponent of a Product

Simplify -2-5...

Question

Simplify $(- 2)^{- 5} \times (3)^{- 5} \times (4)^{- 5}$ .

\frac{1}{(24)^{5}}

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\frac{1}{(- 24)^{5}}

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(- 25)^{5}

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5^{- 5}

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Solution

The correct option is B $\frac{1}{(- 24)^{5}}$
By the Laws of Exponents, we know that $a^{m} \times b^{m} = (a b)^{m}$
$\Rightarrow (- 2)^{- 5} \times (3)^{- 5} \times (4)^{- 5} = ((- 2) \times 3 \times 4)^{- 5} = (- 24)^{- 5} = \frac{1}{(- 24)^{5}}$

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Simplify (−2)−5×(3)−5×(4)−5.

The correct option is B 1(−24)5By the Laws of Exponents, we know that am×bm=(ab)m ⇒(−2)−5×(3)−5×(4)−5=((−2)×3×4)−5=(−24)−5=1(−24)5

Simplify $(- 2)^{- 5} \times (3)^{- 5} \times (4)^{- 5}$ .

The correct option is B $\frac{1}{(- 24)^{5}}$
By the Laws of Exponents, we know that $a^{m} \times b^{m} = (a b)^{m}$
$\Rightarrow (- 2)^{- 5} \times (3)^{- 5} \times (4)^{- 5} = ((- 2) \times 3 \times 4)^{- 5} = (- 24)^{- 5} = \frac{1}{(- 24)^{5}}$