We know, for non zero integers 'a' and 'b' and any integer 'm', a^m× b^m =(a× b)^m Comparing the given expression nbsp;2^ 5× 5^ 5 nbsp;with the LHS of th ...

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Byju's Answer

Standard VII

Mathematics

a^m x b^m = (ab)^m

Simplify 2-5×...

Question

Simplify $2^{- 5} \times - 5^{- 5}$ .

- 10^{5}

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10^{10}

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- 2^{7}

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- 10^{- 5}

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Solution

The correct option is D $- 10^{- 5}$
We know, for non-zero integers 'a' and 'b' and any integer 'm',
$a^{m} \times b^{m} = (a \times b)^{m}$

Comparing the given expression $2^{- 5} \times - 5^{- 5}$ with the LHS of the above equation, we have
a = 2, b = -5 and m = -5.

$∴ 2^{- 5} \times - 5^{- 5} = (2 \times - 5)^{- 5} = - 10^{- 5}$

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Simplify 2−5×−5−5.

The correct option is D −10−5We know, for non-zero integers 'a' and 'b' and any integer 'm', am×bm=(a×b)m Comparing the given expression 2−5×−5−5 with the LHS of the above equation, we have a = 2, b = -5 and m = -5. ∴2−5×−5−5=(2×−5)−5=−10−5

Simplify $2^{- 5} \times - 5^{- 5}$ .