Question

simplify 2*cube root 40 + 3*cube root 625 + 4*cube root 320​

Answer 1

$$\begin{gathered} 2\sqrt[3]{40}+3\sqrt[3]{625}+4\sqrt[3]{320} \\ =2\sqrt[3]{2\times 2\times 2\times 5}+3\sqrt[3]{5\times 5\times 5\times 5}+4\sqrt[3]{2\times 2\times 2\times 2\times 2\times 2\times 5} \\ =4\sqrt[3]{5}+15\sqrt[3]{5}+16\sqrt[3]{5} \\ =35\sqrt[3]{5} \end{gathered}$$