Question

Simplify : $2\log 3+3\log 2+\log 5-\log 12$=logk then k=

Answer 1

$2\log 3+3\log 2+\log 5-\log 12=\log 3^2+\log 2^3+\log 5-\log 12$

$=\log 9+\log 8+\log 5-\log 12$

$=\log 9\times 8\times 5-\log 12$

$=\log 360-\log 12$

$=\log \frac{360}{12}$

$=\log 30$