Question

Simplify: $-21x^5{y}^3÷14x^2{y}^7$.

Answer 1

Simplifying the algebraic expression

The given expression is $-21x^5{y}^3÷14x^2{y}^7$

Here, we have to divide a monomial by another monomial.

We know that,

Quotient of two monomials $=$ (Quotient of their numerical coefficients) (Quotient of their literal coefficients)

Therefore,

$\begin{array}{rcl}-21x^5{y}^3÷14x^2{y}^7& =& \frac{-21\times x^5\times y^3}{14\times x^2\times y^7}\\ & =& -\frac{3\times x^3}{2\times y^4}\\ & =& -\frac{3x^3}{2y^4}\end{array}$

Therefore, simplified result is $-\frac{3x^3}{2y^4}$