Question

Simplify: $({27}^{-2}{)}^{1/3}\times \sqrt{4^3}$

• A. 7/9
• B. 8/9
• C. 9/9
• D. 10/9

Answer 1

The correct option is B 8/9

$({27}^{-2}{)}^{\frac{1}{3}}=3^{-2}$

$(4^3{)}^{\frac{1}{2}}=2^3$

$\therefore ({27}^{-2}{)}^{\frac{1}{3}}\times (4^3{)}^{\frac{1}{2}}=\frac{2^3}{3^2}=\frac{8}{9}$