Simplify $27^{y} = 9 / 3^{y}$ , find $y$ .

Open in App

Solution

A] $27^{y} = 9 / 3^{y}$
$= 27^{y} \times 3^{y} = 9$
$= (3^{3})^{y} \times 3^{y} = 3^{2}$
$= 3^{3 y + y} = 3^{2}$
$3 y + y = 2$
$∴ 4 y = 2$
$\Rightarrow y = 1 / 2$

Suggest Corrections

Similar questions

27^{y} = \frac{9}{3^{y}}

27^{y} = \frac{9}{3^{y}}

27^{y} = \frac{9}{3^{y}}

y

8 x^{3} + 27 y^{3}

2 x + 3 y = 13

x y = 6

\frac{{8 x}^{3} - {27 y}^{3}}{{4 x}^{2} - {9 y}^{2}}

Join BYJU'S Learning Program