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B
(2a+3b)(a−b)=2a2−ab−3b2
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C
(2a+3b)(a−b)=2a2−3b2
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D
(2a+3b)(a−b)=2a2+3b2
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Solution
The correct option is B(2a+3b)(a−b)=2a2+ab−3b2 LHS =(2a+3b)(a−b) =2a(a−b)+3b(a−b) =2a×a−2a×b+3b×a−3b×b =2a2−2ab+3ab−3b2 =2a2+ab−3b2 Thus, (2a+3b)(a−b)≠2a2−3b2, but (2a+3b)(a−b)=2a2+ab−3b2 is the correct statement.