Question

Simplify:

$2a-\left[3b-\left\{a-\left(2c-3b\right)+4c-3(a-b-2c)\right\}\right]$

Answer 1

We have $2a-\left[3b-\left\{a-\left(2c-3b\right)+4c-3(a-b-2c)\right\}\right]$

By BODMAS rule we can solve it as

$$\begin{gathered} =2a-\left[3b-\left\{a-2c+3b+4c-3a+3b+6c\right\}\right] \\ =2a-\left[3b-\left\{a-3a-2c+6c+3b+3b\right\}\right] \\ =2a-\left[3b-\left\{-2a+4c+6b\right\}\right] \\ =2a-\left[3b+2a-4c-6b\right] \\ =2a-\left[-3b+2a-4c\right] \\ =2a+3b-2a+4c \\ =3b+4c \end{gathered}$$

Hence is the required simplification.