Simplify :
$2 a - [4 b - \{4 a - (3 b - \bar{2 a + 2 b}\}]$

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Solution

$= 2 a - [4 b - \{4 a - (3 b - \bar{2 a + 2 b})\}] = 2 a - [4 b - \{4 a - (3 b - 2 a - 2 b\}] (o n r e m o v i n g t h e b a r) = 2 a - [4 b - \{4 a - 3 b - 2 a - 2 b\}] (0 n r e m o v i n g p a r e n t h e s e s) = 2 a - [4 b - 4 a + 3 b + 2 a + 2 b] (o n r e m o v i n g t h e c u r l y b r a c k e t) = 2 a - 4 b + 4 a - 3 b - 2 a - 2 b (o n r e m o v i n g t h e s q u a r e b r a c k e t) = 4 a - 9 b$

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