Question

Simplify $(2q^{-3}{)}^2÷(4q{)}^{1/2}\times (2q^{1/6}{)}^3$ and find the negative of power of $q$

Answer 1

We have,

${\left(2q^{-3}\right)}^2÷{\left(4q\right)}^{1/2}\times {\left(2q^{1/6}\right)}^3$

$\Rightarrow \left(4q^{-6}\right)÷\left(2q^{1/2}\right)\times \left(8q^{1/2}\right)$

$\Rightarrow \left(4q^{-6}\right)÷\left(16q\right)$

$\Rightarrow q^{-7}÷4$

So, the negative power of $q$ is $7$.

Hence, this is the answer.