Simplify $(2 x^{2} + 4 x + 8) - (2 x^{2} - 4 x + 7)$

4 x^{2} + 8 x + 15

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2 x^{2} + x + 1

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8 x + 1

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8 x + 15

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Solution

The correct option is D $8 x + 1$
On simplifying, we get
$(2 x^{2} + 4 x + 8) - (2 x^{2} - 4 x + 7)$
$\Rightarrow 2 x^{2} + 4 x + 8 - 2 x^{2} + 4 x - 7$
$\Rightarrow 8 x + 1$

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Similar questions

2 x^{2} + 5 x - 1 + 8 x + x^{2} + 7 - 6 x + 3 - 3 x^{2}

Which of these statements hold true?

i.) $4 (x - 5) = 4 x - 5$

ii.) $x (3 x + 2) = 3 x^{2} + 2$

iii.) $2 x^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7$ [4 MARKS]

What must be subtracted from $4 x^{3} - 3 x + 5$ to get $2 x^{2} - 3 x^{3} + 5 x - 2$ ?

4 x^{3} - 3 x + 5

2 x^{2} - 3 x^{3} + 5 x - 2

x^{2} - 4 x + 3

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