Given: ( 2x+3y ) ^ 2 We know that: #160; ( a+b ) #160; ^ 2 = a^ 2 +2ab+ b^ 2 Therefore, #160; ( 2x+3y ) ^ 2 #160; =(2x)^2+2× (2x)× ...

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Algebraic Identities

Simplify : 2...

Question

Simplify :
$(2 x + 3 y)^{2}$

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Solution

Given: ${(2 x + 3 y)}^{2}$
We know that: ${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$
Therefore,
${(2 x + 3 y)}^{2}$ $= (2 x)^{2} + 2 \times (2 x) \times (3 y) + (3 y)^{2}$
$= 4 x^{2} + 12 x y + 9 y^{2}$

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