2xy-[4yx-{3xy-(4xy-2xy)}] -----(1)
Let us first solve (4xy-2xy )
4xy-2xy = 2xy
substituting this value in equation 1
2xy-[4yx-{3xy-2xy}] -------(2)
now 3xy-2xy = xy
substituting this value in equation 2
2xy-[4yx-xy]
now yx = xy
thus, 2xy-[4xy-xy] ------(3)
4xy-xy = 3xy
substituting this value in (3)
2xy - 3xy = -xy
answer is -xy