Question

Simplify: $3-\frac{3}{4}-1\frac{2}{3}$

Answer 1

To simplify: $3-\frac{3}{4}-1\frac{2}{3}$

$3-\frac{3}{4}-1\frac{2}{3}$ can also be written as $\frac{3}{1}-\frac{3}{4}-1\frac{2}{3}$.

Convert the above mixed fraction$1\frac{2}{3}$ into improper fractions, we get

$1\frac{2}{3}=\frac{5}{3}$

Now convert the above fractions into like fractions by obtaining L.C.M of their denominators , we get

L.C.M of $1,4$ and$3=12$

$\frac{3}{1}=\frac{3\times 12}{1\times 12}=\frac{36}{12}$

$\frac{3}{4}=\frac{3\times 3}{4\times 3}=\frac{9}{12}$

$\frac{5}{3}=\frac{5\times 4}{3\times 4}=\frac{20}{12}$

$3-\frac{3}{4}-1\frac{2}{3}$ $=\frac{3}{1}-\frac{3}{4}-\frac{5}{3}$

$=\frac{36}{12}-\frac{9}{12}-\frac{20}{12}$

$=\frac{36-9-20}{12}$

$=\frac{7}{12}$

Thus,$3-\frac{3}{4}-1\frac{2}{3}$ $=\frac{7}{12}$ Answer