Question

Simplify [3 MARKS]

$\{{\left(\frac{1}{3}\right)}^{-2}-{\left(\frac{1}{2}\right)}^{-3}\}÷{\left(\frac{1}{4}\right)}^{-2}$

Answer 1

Concept : 1 Mark
Application : 2 Marks

$\{{\left(\frac{1}{3}\right)}^{-2}-{\left(\frac{1}{2}\right)}^{-3}\}÷{\left(\frac{1}{4}\right)}^{-2}$

$=\{\frac{1^{-2}}{3^{-2}}-\frac{1^{-3}}{2^{-3}}\}÷\frac{1^{-2}}{4^{-2}}$

$=\{\frac{3^2}{1^2}-\frac{2^3}{1^3}\}÷\frac{4^2}{1^2}$

$=\{9-8\}÷16$

$=\frac{1}{16}$