Question

Simplify: $3\sqrt[3]{340}-4\sqrt[3]{3320}-\sqrt[3]{35}$

Answer 1

$3\sqrt[3]{340}-4\sqrt[3]{3320}-\sqrt[3]{35}$

$=3\sqrt[3]{38\times 5}-4\sqrt[3]{364\times 5}-\sqrt[3]{35}$

$=3\times 2\sqrt[3]{35}-4\times 4\sqrt[3]{35}-\sqrt[3]{35}$

$=6\sqrt[3]{35}-16\sqrt[3]{35}-\sqrt[3]{35}$

$=-11\sqrt[3]{35}$