Question

Simplify: $\left(\frac{32}{5}\right)+\left(\frac{23}{11}\right)\times \left(\frac{22}{15}\right)$

Answer 1

Simplify the given expression.

Apply BODMAS rule to solve the expression:

$\begin{array}{rcl}\left(\frac{32}{5}\right)+\left(\frac{23}{11}\right)\times \left(\frac{22}{15}\right)& =& \left(\frac{32}{5}\right)+\left(\frac{23}{11}\times \frac{22}{15}\right)\\ & =& \left(\frac{32}{5}\right)+\left(\frac{23}{1}\times \frac{2}{15}\right)\\ & =& \left(\frac{32}{5}\right)+\left(\frac{46}{15}\right)\\ & =& \left(\frac{32\times 3}{5\times 3}\right)+\left(\frac{46}{15}\right)\\ & =& \frac{96}{15}+\frac{46}{15}\\ & =& \frac{96+46}{15}\\ & =& \frac{142}{15}\\ & =& 9\frac{7}{15}\end{array}$

Hence, $\left(\frac{32}{5}\right)+\left(\frac{23}{11}\right)\times \left(\frac{22}{15}\right)=9\frac{7}{15}$.