If x+y+z=0,then x^3+y^3+z^3 3xyz=0 ⇒ x^3+y^3+z^3=3 xyz ( 33)+(25)+(8)=33 33=0 then, ( 33)^3+(25)^3+(8)^3=3× ( 33)× 25× 8 = 19800 Hence, the correct answer ...

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Standard IX

Mathematics

Algebraic Identities

Simplify -333...

Question

Simplify: $(- 33)^{3} + (25)^{3} + (8)^{3}$

20000

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-19800

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19800

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30000

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Solution

The correct option is B
-19800
If $x + y + z = 0, t h e n x^{3} + y^{3} + z^{3} - 3 x y z = 0 \Rightarrow x^{3} + y^{3} + z^{3} = 3 x y z (- 33) + (25) + (8) = 33 - 33 = 0 t h e n, (- 33)^{3} + (25)^{3} + (8)^{3} = 3 \times (- 33) \times 25 \times 8 = - 19800$
Hence, the correct answer is option (b)

Suggest Corrections

Simplify: (−33)3+(25)3+(8)3

The correct option is B -19800If x+y+z=0,thenx3+y3+z3−3xyz=0⇒x3+y3+z3=3 xyz(−33)+(25)+(8)=33−33=0then,(−33)3+(25)3+(8)3=3×(−33)×25×8=−19800 Hence, the correct answer is option (b)

Simplify: $(- 33)^{3} + (25)^{3} + (8)^{3}$