Simplify $3 a (a - b) + b (a + b)$ and then evaluate for $a = 1$ and $b = - 1$ .

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Solution

$= 3 a (a - b) + b (a + b)$

$= 3 a^{2} - 3 a b + b a + b^{2}$

$a = 1$ and $b = - 1.$

$= 3 (1)^{2} - 3 (1) (- 1) + (1) (- 1) + (- 1)^{2}$

$= 3 + 3 - 1 + 1$

$= 6.$

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A

B

A = \frac{1}{1 + x^{b - a} + x^{c - a}} + \frac{1}{1 + x^{c - b} + x^{a - b}} + \frac{1}{1 + x^{a - c} + x^{b - c}}

B = {(\frac{x^{m}}{x^{n}})}^{1 / (m - n)} \times {(\frac{x^{n}}{x^{l}})}^{1 / (n - l)} \times {(\frac{x^{l}}{x^{m}})}^{1 / (l - m)}

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