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Question

Simplify 3a(ab)+b(a+b) and then evaluate for a=1 and b=1.

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Solution

=3a(ab)+b(a+b)

=3a23ab+ba+b2

a=1 and b=1.

=3(1)23(1)(1)+(1)(1)+(1)2

=3+31+1

=6.

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