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Question

Simplify: (3k4r2m)2(3k+4r2m)2

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Solution

=(3k4r2m)2(3k+4r2m)2
=[(3k)2+(4r)2+(2m)2+{2×(3k)×(4r)}
+{2×(4r)×(2m}+{2×(3k)×(2m)}]
[(3k)2+(4r)2+(2m)2+{2×(3k)×(4r)}
+{2×4r×(2m)}+{2×(3k)×(2m)}]
By using the formula,
(a+b+c)2=a2+b2+c2+2ab+2bc+2ac
=[9k2+16r2+4m2+{24kr}+{16rm}+{12km}]
[9k2+16r2+4m2+{24kr}+{16rm}+{12km}]
=[9k2+16r2+4m224kr+16rm12km]
[9k2+16r2+4m2+24kr16rm12km]
=9k2+16r2+4m224kr+16rm12km9k216r24m224kr+16rm+12km
=48kr+32rm
=32rm48kr
(3k4r2m)2(3k+4r2m)2=32rm48kr

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