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Byju's Answer
Standard X
Mathematics
Formula for Sum of n Terms of an AP
Simplify: 3...
Question
Simplify:
{
(
3
x
2
−
6
x
+
5
)
+
(
2
x
−
2
x
2
+
5
)
}
−
(
x
2
−
4
x
+
10
)
Open in App
Solution
Let us solve the given expression
[
(
3
x
2
−
6
x
+
5
)
+
(
2
x
−
2
x
2
+
5
)
]
−
(
x
2
−
4
x
+
10
)
as shown below:
[
(
3
x
2
−
6
x
+
5
)
+
(
2
x
−
2
x
2
+
5
)
]
−
(
x
2
−
4
x
+
10
)
=
(
3
x
2
−
6
x
+
5
+
2
x
−
2
x
2
+
5
)
−
(
x
2
−
4
x
+
10
)
=
[
(
3
x
2
−
2
x
2
)
+
(
−
6
x
+
2
x
)
+
(
5
+
5
)
]
−
(
x
2
−
4
x
+
10
)
(
C
o
m
b
i
n
i
n
g
l
i
k
e
t
e
r
m
s
)
=
[
(
3
−
2
)
x
2
+
(
−
6
+
2
)
x
+
10
]
−
(
x
2
−
4
x
+
10
)
=
(
x
2
−
4
x
+
10
)
−
(
x
2
−
4
x
+
10
)
=
0
Hence,
[
(
3
x
2
−
6
x
+
5
)
+
(
2
x
−
2
x
2
+
5
)
]
−
(
x
2
−
4
x
+
10
)
=
0
.
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0
Similar questions
Q.
Subtract:
2
x
2
+
6
−
4
x
from
3
x
2
−
6
x
+
8.
Q.
Subtracting
2
x
2
+
6
−
4
x
from
3
x
2
−
6
x
+
8
gives
.
Q.
Simplify:
(
1
+
1
2
x
+
1
√
3
x
2
)
+
(
5
−
2
3
+
√
3
x
2
)
-
(
4
−
1
3
x
−
2
√
3
x
2
)
Answer:
1
+
1
6
x
+
10
√
3
x
2
Q.
Form the sum of
(
4
+
3
x
−
x
2
)
and
(
5
−
4
x
+
2
x
2
)
, subtract the sum of
(
3
x
2
−
5
x
)
and
(
−
x
2
+
2
x
+
5
)
.
Q.
(i) Simplify:
(
x
3
–
2
x
2
+
3
x
–
4
)
(
x
–
1
)
–
(
2
x
–
3
)
(
x
2
–
x
+
1
)
(ii) Simplify:
x
2
(
x
–
y
)
y
2
(
x
+
2
y
)
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