Simplify: $(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)$

$0$

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$- 4 y^{2} + 6 x y$

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$2 y (- 2 y + 3 x)$

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Both B and C

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Solution

The correct option is B
$- 4 y^{2} + 6 x y$

$(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)$

$= (9 x^{2} + 12 x y - 6 x y - 8 y^{2}) - (9 x^{2} - 4 y^{2})$
$= (9 x^{2} + 6 x y - 8 y^{2}) - (9 x^{2} - 4 y^{2})$

$= - 4 y^{2} + 6 x y$

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Similar questions

Simplify: (3x-2y)(3x+4y)-(3x+2y)(3x-2y)

\frac{(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)}{(- 4 y^{2} + 6 x y)}

(3 x - \frac{1}{2 y}) (3 x + \frac{1}{2 y})

9 x^{2} - 4 y^{2}

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