Simplify: (3x-2y)(3x+4y)-(3x+2y)(3x-2y)
(3x−2y)(3x+4y)−(3x+2y)(3x−2y)=(9x2+6xy−8y2)−[9x2−4y2]=−4y2+6xy
Factorise :
4x(3x−2y)−2y(3x−2y)
Find the continued products: (i) (x+1)(x−1)(x2+1) (ii) (x−3)(x+3)(x2+9) (iii) (3x−2y)(3x+2y)(9x2+4y2) (iv) (2p+3)(2p−3)(4p2+9)