Question

simplify
$3x+\frac{1}{2}=\frac{3}{8}+\frac{x}{8}$

Answer 1

$3x+\frac{1}{2}=\frac{3}{8}+\frac{x}{8}$

$\Rightarrow 3x-\frac{x}{8}=\frac{3}{8}-\frac{1}{2}$

$\Rightarrow \frac{24x-x}{8}=\frac{3}{8}-\frac{4}{8}$

$\Rightarrow \frac{23x}{8}=\frac{3-4}{8}$

$\Rightarrow 23x=-1$

$\therefore x=-\frac{1}{23}$