Simplify : 4(1 – sin2θ) (1 + tan2θ)
4
1
2
0
Using the identity, 1 - sin2θ = cos2θ and 1 + tan2θ = sec2θ
We have, 4(1 – sin2θ) (1 + tan2θ) =4 cos2θ×sec2θ=4 (∵sec θ=1cos θ)
Solve: 4[1–sin2θ][1+tan2θ]