Simplify: $(4^{1000}) (8^{2000}) (16^{- 2000})$

2

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3

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4

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1

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5

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Solution

The correct option is B $1$
$(4^{1000}) (8^{2000}) (16^{- 2000})$
$= ({[2^{2}]}^{1000}) ({[2^{3}]}^{2000}) ({[2^{4}]}^{- 2000})$
$= (2^{2000}) (2^{6000}) (2^{- 8000})$
$= 2^{(2000 + 6000 - 8000)} = (2)^{0}$
$= 1$

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