Simplify : $4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}$

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Solution

$4^{- 2} + 4^{- 1} + 4^{0} + 4^{2} = \frac{1}{16} + \frac{1}{4} + 1 + 16$

$= \frac{1 + 4 + 16 + 256}{16}$

$= \frac{277}{16}$

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