Question

Simplify
$4^4\times {16}^{-2}\times 4^0$

Answer 1

$4^4\times {16}^{-2}\times 4^0$
$4^4\times {\left(4^2\right)}^{-2}\times 4^0$ $(\because {\left(a^m\right)}^n=a^{mn})$
$=4^4\times 4^{-4}\times 4^0$ $(\because a^m\times a^n=a^{m+n})$
$=4^{4+4+0}=4^0$
$=1$ ($\because a^0=1$)