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Byju's Answer
Standard VI
Mathematics
Subtraction of Fractions
Simplify : 4...
Question
Simplify :
4
2
3
+
3
1
4
+
7
1
2
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Solution
4
2
3
+
3
1
4
+
7
1
2
=
14
3
+
13
4
+
15
2
L
.
C
.
M
o
f
2
,
3
,
4
i
s
12
=
14
∗
4
+
13
∗
3
+
15
∗
6
12
=
56
+
39
+
90
12
=
185
12
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Q.
Simplify the following
(a) 12 + [{1 + (15 − 3)} × 4]
(b)
(c)
(d)
(e)