Question

Simplify $4\sqrt{3}+6\sqrt{27}$.

• A. $22\sqrt{3}$
• B. $20\sqrt{2}7$
• C. $12\sqrt{3}$
• D. $22\sqrt{2}7$

Answer 1

Answer: (A)

$22\sqrt{3}$

Given that $4\sqrt{3}+6\sqrt{27}$

$4\sqrt{3}+6\sqrt{3\times 3\times 3}$

$4\sqrt{3}+6\times 3\sqrt{3}$

$\sqrt{3}(4+18)$

$22\sqrt{3}$ Ans.