Simplify- 420-7 of 2-3-84 of 3-12-15

Simplifying using BODMAS rule.=420÷7 of 2/3 (84 of 3÷12+15)=420÷7 of 2/3 (84×3/12+15)=420÷7 of 2/3 (21+15)=420÷7 of 2/3 36=420÷14/3 36=420×3/14 36=90 36=54.Henc ...

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Byju's Answer

Standard IX

Mathematics

Algebraic Identities

Simplify: 420...

Question

Simplify: $420 \div 7 o f \frac{2}{3} - (84 o f 3 \div 12 + 15)$

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Solution

Simplifying using BODMAS rule.
$= 420 \div 7 o f \frac{2}{3} - (84 o f 3 \div 12 + 15)$
$= 420 \div 7 o f \frac{2}{3} - (84 \times \frac{3}{12} + 15)$
$= 420 \div 7 o f \frac{2}{3} - (21 + 15)$
$= 420 \div 7 o f \frac{2}{3} - 36$
$= 420 \div \frac{14}{3} - 36$
$= 420 \times \frac{3}{14} - 36$
$= 90 - 36$
$= 54$ .
Hence, $420 \div 7 o f \frac{2}{3} - (84 o f 3 \div 12 + 15)$ on simplifying gives $54$ .

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Simplify: 420÷7of23-84of3÷12+15

Simplifying using BODMAS rule.=420÷7of23-84of3÷12+15=420÷7of23-84×312+15=420÷7of23-21+15=420÷7of23-36=420÷143-36=420×314-36=90-36=54.Hence, 420÷7of23-84of3÷12+15 on simplifying gives 54.

Simplify: $420 \div 7 o f \frac{2}{3} - (84 o f 3 \div 12 + 15)$