Simplify

4st(s − t) −6s²(t − t²) −3t² (2s²− s) +2st (s − t)

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Solution

$4 st (s - t) - 6 s^{2} (t - t^{2}) - 3 t^{2} (2 s^{2} - s) + 2 st (s - t) = 4 st \times s - 4 st \times t - 6 s^{2} \times t - 6 s^{2} \times (- t^{2}) - 3 t^{2} \times 2 s^{2} - 3 t^{2} \times (- s) + 2 st \times s - 2 st \times t = 4 \times s^{(1 + 1)} \times t - 4 \times s \times t^{(1 + 1)} - 6 s^{2} t + 6 s^{2} t^{2} - 6 t^{2} s^{2} + 3 t^{2} s + 2 \times s^{(1 + 1)} \times t - 2 \times s \times t^{(1 + 1)} = 4 s^{2} t - 4 {st}^{2} - 6 s^{2} t + 6 s^{2} t^{2} - 6 t^{2} s^{2} + 3 t^{2} s + 2 s^{2} t - 2 {st}^{2} = 4 s^{2} t - 6 s^{2} t + 2 s^{2} t - 4 {st}^{2} + 3 {st}^{2} - 2 {st}^{2} = - 3 {st}^{2}$

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Similar questions

The simplest algebraic expression of $4 s t (s - t) - 6 s^{2} (t - t^{2}) - 3 t^{2} (2 s^{2} - s) + 2 s t (s - t)$ is _________.

The product of $(t + s^{2})$ and $(t^{2} - s)$ is:

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