Given expression is , #160; 4y(3y+4) Multiplying the factors, we get, =4y× 3y+4y× 4 =12y^2+16y Hence, #160; #160; 4y(3y+4)=12y^2+16y # ...

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Multiplication of Monomials

Simplify: 4...

Question

Simplify: $4 y (3 y + 4)$

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Solution

Given expression is ,
$4 y (3 y + 4)$
Multiplying the factors, we get,
$= 4 y \times 3 y + 4 y \times 4$
$= 12 y^{2} + 16 y$

Hence, $4 y (3 y + 4) = 12 y^{2} + 16 y$

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