(i) When the number of terms is 20
5 + (− 5) + 5 + (− 5) + ... = (5 + 5 + 5 + ... + 10 terms) + (− 5) + 5 + (− 5) + ... + 10 terms
= 10 5 + 10 (− 5)
= 50 − 50
= 0
(ii) When the number of terms is 25
5 + (− 5) + 5 + (− 5) + ... = (5 + 5 + 5 + ... + 12 terms) + (− 5) + 5 + (− 5) + ... + 13 terms
= 12 5 + 13 (− 5)
= 60 − 65
= − (65 − 60)
= − 5