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Addition of Fractions

Simplify ;5 [...

Question

Simplify ;
$5 [6 - \{7 + 2 - (5 + 4 \div 7 o f 6 + \bar{2 \times 3 - 5})\}]$

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Solution

$5 [6 - \{7 + 2 - (5 + 4 \div 7 o f 6 + \bar{2 \times 3 - 5})\}] = 5 [6 - \{7 + 2 - (5 + 4 \div 7 o f 6 + \bar{6 - 5})\}]$
$= 5 [6 - \{7 + 2 - (5 + 4 \div 7 o f 6 + 1)\}]$
$= 5 [6 - \{7 + 2 - (5 + 4 \div 7 o f 6 + 1)\}] = 5 [6 - \{7 + 2 - (5 + 4 \div 42 + 1)\}] = 5 [6 - \{7 + 2 - (5 + \frac{4}{42} + 1)\}] = 5 [6 - \{7 + 2 - (5 + \frac{2}{21} + 1)\}] = 5 [6 - \{7 + 2 - (\frac{5 \times 21 + 2 + 1 \times 21}{21})\}] = 5 [6 - \{7 + 2 - (\frac{105 + 2 + 21}{21})\}] = 5 [6 - \{7 + 2 - (\frac{128}{21})\}] = 5 [6 - \{9 - \frac{128}{21}\}] = 5 [6 - \{\frac{9 \times 21 - 128}{21}\}] = 5 [6 - \{\frac{189 - 128}{21}\}] = 5 [6 - \{\frac{61}{21}\}] = 5 [\frac{6 \times 21 - (61)}{21}] = 5 [\frac{126 - 61}{21}] = 5 \times [\frac{65}{21}] = \frac{325}{21}$
Hence, the simplified answer is $\frac{325}{21} .$

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