Simplify

(5x − 3)(x + 4) − (2x + 5)(3x − 4)

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Solution

(5x-3)(x+4)

$= 5 x \times (x + 4) - 3 \times (x + 4) = 5 x^{(1 + 1)} + 20 x - 3 x - 12 = 5 x^{2} + 17 x - 12$

(2x +5)(3x-4)

$= 2 x \times (3 x - 4) + 5 \times (3 x - 4) = 6 x^{(1 + 1)} - 8 x + 15 x - 20 = 6 x^{2} + 7 x - 20$

∴ (5x − 3)(x + 4) − (2x + 5)(3x − 4)

$= 5 x^{2} + 17 x - 12 - (6 x^{2} + 7 x - 20) = 5 x^{2} - 6 x^{2} + 17 x - 7 x - 12 + 20 = - x^{2} + 10 x + 8$

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Similar questions

Non-negative root of ${(\frac{3 x - 1}{2 x + 3})}^{2} - 5 (\frac{3 x - 1}{2 x + 3}) + 4 = 0$ is _____.

{(\frac{3 x - 1}{2 x + 3})}^{2} - 5 (\frac{3 x - 1}{2 x + 3}) + 4 = 0

Find the non-negative root of ${(\frac{3 x - 1}{2 x + 3})}^{2} - 5 (\frac{3 x - 1}{2 x + 3}) + 4 = 0$

\frac{2 x + 5}{3 x + 4} = 3

Solve:-

(i) $5 (3 x - 4) - 8 (6 x - 7) = 9 x - 8$

(ii) $2 x - \frac{3 x}{5} = 7$

(iii) $\frac{2 z}{3} - 5 = \frac{3 z}{4} - 1$

(iv) $\frac{4 x}{7} - 12 = 7$

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