Simplify:

(6) [(15) × (2) + (–4) × (5)] ÷ (–5)

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Solution

We follow the BODMAS rule in simplifying the expression.
BODMAS: Brackets open, Division, Multiplication, Addition and Subtraction (in the given order)

Now, [(15) × (2) + (–4) × (5)] ÷ (–5)
= [30 – 20] ÷ (–5) (Performing the multiplication in the square brackets first)
= 10 ÷ (–5) (Solving the subtraction in the square brackets)
= $\frac{10}{- 5} = \frac{- 10}{5}$
= –2

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Similar questions

4 \frac{1}{10} - [2 \frac{1}{2} - {\frac{5}{6} - (\frac{2}{5} + \frac{3}{10} - \frac{4}{15})}]

Simplify:

(1) $2 + (- 4) - (+ 3)$

(2) $- 5 + 4 - (- 2)$

(3) $10 + (- 5) - (- 4)$

(4) $12 - (+ 6) + (- 3)$

(5) $- 15 + (- 4) - (+ 3)$

\frac{10^{2} \times 15^{3}}{2^{2} \times 3 \times 5^{5} \times 6^{4}}

(- 5 \times (2 / 15)) - (- 6 \times (2 / 9))

\frac{1}{6} + \frac{- 2}{5} - \frac{- 2}{15}

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