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Addition of Fractions

Simplify : 6...

Question

Simplify :
$6 + {\frac{4}{3} + (\frac{3}{4} - \frac{1}{3})}$

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Solution

$6 + {\frac{4}{3} + (\frac{3}{4} - \frac{1}{3})}$
$= 6 + \frac{4}{3} + \frac{3}{4} - \frac{1}{3}$
$= \frac{72 + 16 + 9 - 4}{12}$ = $\frac{93}{12}$

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