Question

Simplify:
$(-72l^4{m}^5{n}^8)÷(-8l^2{m}^2{n}^3)$

Answer 1

$\frac{-72l^4{m}^5{n}^8}{-8l^2{m}^2{n}^3}$

$=\frac{9l^4{m}^5{n}^8}{l^2{m}^2{n}^3}$

$=\frac{9l^2{m}^5{n}^8}{m^2{n}^3}$

$=\frac{9l^2{m}^3{n}^8}{n^3}$

$=9l^2{m}^3{n}^5$