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Byju's Answer

Standard VII

Mathematics

Using Brackets

Simplify:8-31...

Question

Simplify:
$8 - 3 \frac{1}{2} - 2 \frac{1}{4}$

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Solution

We have:
$8 - 3 \frac{1}{2} - 2 \frac{1}{4} = \frac{8}{1} - \frac{7}{2} - \frac{9}{4} 2 1, 2, 4 2 1, 1, 2 1, 1, 1 L . C . M . of 1, 2 and 4 = (2 \times 2) = 4 = \frac{(32 - 14 - 9)}{4} \{[4 \div 1 = 4, 4 \times 8 = 32], [4 \div 2 = 2, 2 \times 7 = 14] and [4 \div 4 = 1, 1 \times 9 = 9]\} = \frac{(32 - 23)}{4} = \frac{9}{4} = 2 \frac{1}{4}$

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Similar questions

Simplify:
(i) $\frac{2}{3} + \frac{5}{6} - \frac{1}{9}$
(ii) $8 - 4 \frac{1}{2} - 2 \frac{1}{4}$
(iii) $8 \frac{5}{6} - 3 \frac{3}{8} + 1 \frac{7}{12}$

Q. Simplify:

7 \frac{1}{2} - [2 \frac{1}{4} \div \{1 \frac{1}{4} - \frac{1}{2} (\frac{3}{2} - \bar{\frac{1}{3} - \frac{1}{6}})\}]

Q. Simplify:

{(\frac{- 4}{3})}^{8} \div {(\frac{- 4}{3})}^{12}

Q. Simplify:
(i)

\frac{2}{3} + \frac{1}{6} - \frac{2}{9}

(ii)

12 - 3 \frac{1}{2}

(iii)

7 \frac{5}{6} - 4 \frac{3}{8} + 2 \frac{7}{12}

\frac{8}{2^{2} + 1} + \frac{16}{2^{6} + 1} + \frac{32}{2^{14} + 1} + \frac{64}{2^{14} + 1} + \frac{128}{2^{18} + 1} =

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Simplify: 8-312-214

We have: 8 - 312 -214 = 81 - 72 - 94 2 1, 2, 4 2 1, 1, 2 1, 1, 1 L.C.M. of 1, 2 and 4 = (2 × 2) = 4 = 32 - 14 - 94 4 ÷ 1 =4, 4 × 8 = 32, 4 ÷ 2 =2, 2 × 7 = 14 and 4 ÷ 4 =1, 1 × 9 = 9 = 32 - 234 = 94 = 214

Simplify:
$8 - 3 \frac{1}{2} - 2 \frac{1}{4}$